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Problem 44


Problem 44


Pentagon Numbers

Pentagonal numbers are generated by the formula, Pn=n(3n1)/2. The first ten pentagonal numbers are:

1,5,12,22,35,51,70,92,117,145,

It can be seen that P4+P7=22+70=92=P8. However, their difference, 7022=48, is not pentagonal.

Find the pair of pentagonal numbers, Pj and Pk, for which their sum and difference are pentagonal and D=|PkPj| is minimised; what is the value of D?


五边形数

五边形数由公式Pn=n(3n1)/2给出。前十个五边形数是:

1,5,12,22,35,51,70,92,117,145,

可以看出P4+P7=22+70=92=P8。然而,它们的差7022=48并不是五边形数。

在所有和差均为五边形数的五边形数对PjPk中,找出使D=|PkPj|最小的一对;此时D的值是多少?


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