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Problem 450


Problem 450


Hypocycloid and Lattice points

A hypocycloid is the curve drawn by a point on a small circle rolling inside a larger circle. The parametric equations of a hypocycloid centered at the origin, and starting at the right most point is given by:

x(t)=(Rr)cos(t)+rcos(Rrrt) y(t)=(Rr)sin(t)rsin(Rrrt)

Where R is the radius of the large circle and r the radius of the small circle.

Let C(R,r) be the set of distinct points with integer coordinates on the hypocycloid with radius R and r and for which there is a corresponding value of t such that sin(t) and cos(t) are rational numbers.

Let S(R,r)=(x,y)C(R,r)|x|+|y| be the sum of the absolute values of the x and y coordinates of the points in C(R,r).

Let T(N)=R=3Nr=1R12S(R,r) be the sum of S(R,r) for R and r positive integers, RN and 2r<R.

You are given:
C(3, 1) = {(3, 0), (-1, 2), (-1,0), (-1,-2)}

C(2500, 1000) =

{(2500, 0), (772, 2376), (772, -2376), (516, 1792),(516, -1792), (500, 0), (68, 504), (68, -504),(-1356, 1088), (-1356, -1088), (-1500, 1000), (-1500, -1000)}

Note: (-625, 0) is not an element of C(2500, 1000) because sin(t) is not a rational number for the corresponding values of t.

S(3, 1) = (|3| + |0|) + (|-1| + |2|) + (|-1| + |0|) + (|-1| + |-2|) = 10

T(3) = 10; T(10) = 524; T(100) = 580442; T(103) = 583108600.

Find T(106).


圆内旋轮线与格点

在大圆内部有一小圆与其相切并不断滚动,由小圆上一点所构成的曲线称为圆内旋轮线。以原点为圆心,以最右侧的点为起点的圆内旋轮线,其参数方程如下所示:

x(t)=(Rr)cos(t)+rcos(Rrrt) y(t)=(Rr)sin(t)rsin(Rrrt)

其中R是大圆的半径,而r是小圆的半径。

C(R,r)是大小圆半径分别为R和r时落在圆内旋轮线上的格点的集合,且此时对应的t值满足sin(t)cos(t)都是有理数。

S(R,r)=(x,y)C(R,r)|x|+|y|C(R,r)中所有点的坐标绝对值之和。

T(N)=R=3Nr=1R12S(R,r)是满足R和r均为正整数,RN以及2r<R的所有S(R,r)的和。

已知:
C(3, 1) = {(3, 0), (-1, 2), (-1,0), (-1,-2)}

C(2500, 1000) =

{(2500, 0), (772, 2376), (772, -2376), (516, 1792),(516, -1792), (500, 0), (68, 504), (68, -504),(-1356, 1088), (-1356, -1088), (-1500, 1000), (-1500, -1000)}

注意:(-625, 0)不是C(2500, 1000)中的元素,此时对应的t值不满足sin(t)为有理数。

因此S(3, 1) = (|3| + |0|) + (|-1| + |2|) + (|-1| + |0|) + (|-1| + |-2|) = 10

且已知T(3) = 10;T(10) = 524;T(100) = 580442;T(103) = 583108600。

求T(106)。


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