Problem 50

Consecutive Prime Sum

The prime $41$ , can be written as the sum of six consecutive primes:

$41 = 2 + 3 + 5 + 7 + 11 + 13$

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains $21$ terms, and is equal to $953$ .

Which prime, below one-million, can be written as the sum of the most consecutive primes?

素数 $41$ 可以写成六个连续素数的和：

$41 = 2 + 3 + 5 + 7 + 11 + 13$

在小于一百的素数中， $41$ 能够被写成最多的连续素数的和。

在小于一千的素数中， $953$ 能够被写成最多的连续素数的和，共包含连续 $21$ 个素数。

在小于一百万的素数中，哪个素数能够被写成最多的连续素数的和？