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Problem 136


Problem 136


Singleton difference

The positive integers, x, y, and z, are consecutive terms of an arithmetic progression. Given that n is a positive integer, the equation, x2 − y2 − z2 = n, has exactly one solution when n = 20:

132 − 102 − 72 = 20

In fact there are twenty-five values of n below one hundred for which the equation has a unique solution.

How many values of n less than fifty million have exactly one solution?


唯一的差

正整数x,y,z构成等差数列。取正整数n=20,此时方程x2 − y2 − z2 = n只有一个解:

132 − 102 − 72 = 20

事实上,在小于一百的数中,有25个n的取值使得方程有唯一解。

在小于五千万的数中,有多少个n的取值使得方程有唯一解?