Problem 50
Consecutive prime sum
The prime $41$, can be written as the sum of six consecutive primes:
$$41 = 2 + 3 + 5 + 7 + 11 + 13$$
This is the longest sum of consecutive primes that adds to a prime below one-hundred.
The longest sum of consecutive primes below one-thousand that adds to a prime, contains $21$ terms, and is equal to $953$.
Which prime, below one-million, can be written as the sum of the most consecutive primes?
连续素数的和
素数$41$可以写成六个连续素数的和：
$$41 = 2 + 3 + 5 + 7 + 11 + 13$$
在小于一百的素数中，$41$能够被写成最多的连续素数的和。
在小于一千的素数中，$953$能够被写成最多的连续素数的和，共包含连续$21$个素数。
在小于一百万的素数中，哪个素数能够被写成最多的连续素数的和？