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# Problem 573

## Unfair race

$n$ runners in very different training states want to compete in a race. Each one of them is given a different starting number $k$ $(1\leq k \leq n)$ according to his (constant) individual racing speed being $v_k=\frac{k}{n}$.
In order to give the slower runners a chance to win the race, $n$ different starting positions are chosen randomly (with uniform distribution) and independently from each other within the racing track of length 1. After this, the starting position nearest to the goal is assigned to runner 1, the next nearest starting position to runner 2 and so on, until finally the starting position furthest away from the goal is assigned to runner $n$. The winner of the race is the runner who reaches the goal first.

Interestingly, the expected running time for the winner is $\frac{1}{2}$, independently of the number of runners. Moreover, while it can be shown that all runners will have the same expected running time of $\frac{n}{n+1}$, the race is still unfair, since the winning chances may differ significantly for different starting numbers:

Let $P_{n,k}$ be the probability for runner $k$ to win a race with $n$ runners and $E_n = \sum_{k=1}^n k P_{n,k}$ be the expected starting number of the winner in that race. It can be shown that, for example,
$P_{3,1}=\frac{4}{9}$, $P_{3,2}=\frac{2}{9}$, $P_{3,3}=\frac{1}{3}$ and $E_3=\frac{17}{9}$ for a race with 3 runners.
You are given that $E_4=2.21875$, $E_5=2.5104$ and $E_{10}=3.66021568$.

Find $E_{1000000}$ rounded to 4 digits after the decimal point.

## 不公平的比赛

$n$名处于不同训练状态的跑步选手想要进行一场比赛。他们每个人拥有一个不同的初始编号$k$ $(1\leq k \leq n)$，相应地他们各自（固定的）跑步速度为$v_k=\frac{k}{n}$。

$P_{3,1}=\frac{4}{9}$，$P_{3,2}=\frac{2}{9}$，$P_{3,3}=\frac{1}{3}$，因此对于有3名选手参加的比赛$E_3=\frac{17}{9}$。