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Problem 858


Problem 858


LCM

Define G(N)=Slcm(S) where S ranges through all subsets of 1,,N and lcm denotes the lowest common multiple. Note that the lcm of the empty set is 1.

You are given G(5)=528 and G(20)=8463108648960.

Find G(800). Give your answer modulo 109+7.


最小公倍数

定义G(N)=Slcm(S),其中S取遍1,,N的所有子集,lcm表示最小公倍数。注意对空集取lcm的结果为1

已知G(5)=528G(20)=8463108648960

G(800),并对109+7取余作为你的答案。


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