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Problem 38


Problem 38


Pandigital Multiples

Take the number 192 and multiply it by each of 1, 2, and 3:

192×1=192

192×2=384

192×3=576

By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2,,n) where n>1?


全数字的倍数

192分别与123相乘:

192×1=192

192×2=384

192×3=576

将这些乘积拼接起来,可以得到一个19全数字的数192384576,因此称192384576192(1,2,3)的拼接乘积。

类似地,将9分别与12345相乘,可以得到19全数字的数918273645,并称之为9(1,2,3,4,5)的拼接乘积。

考虑所有n>1时某个整数和(1,2,,n)的拼接乘积,其中最大的19全数字的数是多少?


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